Calculus Find dy/dx x^2xyy^3=0 x2 xy y3 = 0 x 2 x y y 3 = 0 Differentiate both sides of the equation d dx (x2 xy y3) = d dx (0) d d x ( x 2 x y y 3) = d d x ( 0) Differentiate the left To prove x 3 −y 3 =(x−y)(x 2 xyy 2) Consider the right hand side (RHS) and expand it as follows (x−y)(x 2 xyy 2)=x 3 x 2 yxy 2 −yx 2 −xy 2 −y 3 =(xThat is (xy) ( x 2 xy y 2) = (xy) ( x 2 xy y 2) Hence verified that x 3 y 3 = (xy) ( x 2 xy y 2 ) Although, for verifying the first step is mostly used !
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X 3+y 3 x+y x 2-xy+y 2-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreExpand (x−y)(x− y) ( x y) ( x y) using the FOIL Method Tap for more steps x⋅xx(−y)−yx−y(−y)3(y− x)3 x ⋅ x x ( y) y x y ( y) 3 ( y x) 3 Simplify and combine
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Click here👆to get an answer to your question ️ Verify x^3 y^3 = (x y)(x^2 xy y^2)Solution We have, x 3 y 3 = ( x y) ( x 2 – xy y 2) In the given equation LHS = x 3 y 3 RHS = ( x y) ( x 2 – xy y 2) We know that, ( x y) 3 = x 3 y 3 3 xy ( x y) ⇒ x 3 y 3 = ( x y) This question aims to find all the secondorder partial derivatives of the given function The derivative of a function with more than one variable with respect to one of the
Solve x2 (y −1)2 (x−y)2 − 31 = 0 Solving the quadratic equation x2 (y−1)2 (x− y)2 = 31 (where the unknown is x) gives you x = 6(3y− 3 −9y212y−4) But −9y2 12y− 4 = −(3y −2)2
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